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Move tint::ast::type to tint::type
Despite `tint::ast::type::Type` being in the AST namespace, these classes are clearly not AST nodes: * They don't derive from ast::Node * They're deduplicated by the type manager * None of the types have an Source - they have no lexical declaration point * The fact we have `ast::Struct` and `ast::type::Struct` clearly demonstrates what is an AST node, and what is a type. * We have code scattered in the codebase (TypeDeterminer, writers, etc) that create new types after parsing - so clearly not part of the original syntax tree. Types in tint are closer to being semantic info, but due to the parse-time generation of types, and tight dependency of ast::Nodes to types, I'd be reluctant to class these as semantic info. Instead, put these into a separate root level `tint::type` namespace and `src/tint` directory. The fact that types exist in the ast::Module has already caused bugs (https://dawn-review.googlesource.com/c/tint/+/37261). This is a first step in separating out types from the ast::Module. Bug: tint:390 Change-Id: I8349bbbd1b19597b8e6d51d5cda0890de46ecaec Reviewed-on: https://dawn-review.googlesource.com/c/tint/+/38002 Commit-Queue: Ben Clayton <bclayton@google.com> Reviewed-by: dan sinclair <dsinclair@chromium.org>
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@@ -67,7 +67,7 @@ extern "C" int LLVMFuzzerTestOneInput(const uint8_t* data, size_t size) {
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for (auto* src_node : src.nodes()) {
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src_nodes.emplace(src_node);
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}
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std::unordered_set<tint::ast::type::Type*> src_types;
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std::unordered_set<tint::type::Type*> src_types;
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for (auto& src_type : src.types()) {
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src_types.emplace(src_type.second.get());
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}
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