Fix default case must at last assertion in Switch()
Fix an assertion in SwitchCases that default case must be last in Switch(). Change-Id: I5ece5a20e22f8df607581373d1f0bb0bd44fb58b Reviewed-on: https://dawn-review.googlesource.com/c/tint/+/85461 Kokoro: Kokoro <noreply+kokoro@google.com> Reviewed-by: Ben Clayton <bclayton@google.com> Commit-Queue: Zhaoming Jiang <zhaoming.jiang@intel.com>
This commit is contained in:
parent
79db32aff2
commit
4bc30b7ba2
|
@ -641,7 +641,8 @@ inline void SwitchCases(T* object,
|
|||
std::tuple<CASES...>&& cases) {
|
||||
using Cases = std::tuple<CASES...>;
|
||||
static constexpr int kDefaultIndex = detail::IndexOfDefaultCase<Cases>();
|
||||
static_assert(kDefaultIndex == -1 || std::tuple_size_v<Cases> - 1,
|
||||
static_assert(
|
||||
kDefaultIndex == -1 || kDefaultIndex == std::tuple_size_v<Cases> - 1,
|
||||
"Default case must be last in Switch()");
|
||||
static constexpr bool kHasDefaultCase = kDefaultIndex >= 0;
|
||||
static constexpr bool kHasReturnType = !std::is_same_v<RETURN_TYPE, void>;
|
||||
|
|
Loading…
Reference in New Issue