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Correct use of constexpr

This commit is contained in:
Jack Andersen 2016-07-31 18:33:29 -10:00
parent cf3dfcddff
commit 750d23c686
1 changed files with 3 additions and 3 deletions
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6
include/athena/Global.hpp
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@ -87,19 +87,19 @@ constexpr type operator&(type a, type b)\
using T = std::underlying_type_t<type>;\ using T = std::underlying_type_t<type>;\
return type(static_cast<T>(a) & static_cast<T>(b));\ return type(static_cast<T>(a) & static_cast<T>(b));\
}\ }\
constexpr type& operator|=(type& a, const type& b)\ inline type& operator|=(type& a, const type& b)\
{\ {\
using T = std::underlying_type_t<type>;\ using T = std::underlying_type_t<type>;\
a = type(static_cast<T>(a) | static_cast<T>(b));\ a = type(static_cast<T>(a) | static_cast<T>(b));\
return a;\ return a;\
}\ }\
constexpr type& operator&=(type& a, const type& b)\ inline type& operator&=(type& a, const type& b)\
{\ {\
using T = std::underlying_type_t<type>;\ using T = std::underlying_type_t<type>;\
a = type(static_cast<T>(a) & static_cast<T>(b));\ a = type(static_cast<T>(a) & static_cast<T>(b));\
return a;\ return a;\
}\ }\
constexpr type operator~(const type& key)\ inline type operator~(const type& key)\
{\ {\
using T = std::underlying_type_t<type>;\ using T = std::underlying_type_t<type>;\
return type(~static_cast<T>(key));\ return type(~static_cast<T>(key));\