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Correct use of constexpr

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This commit is contained in:
Jack Andersen 2016-07-31 18:34:54 -10:00 committed by Phillip Stephens
parent 4ccc8bd3c1
commit 2d4c021509
1 changed files with 3 additions and 3 deletions
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6
include/kabufuda/Util.hpp
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@ -46,19 +46,19 @@ constexpr type operator&(type a, type b)\
using T = std::underlying_type_t<type>;\
return type(static_cast<T>(a) & static_cast<T>(b));\
}\
constexpr type& operator|=(type& a, const type& b)\
inline type& operator|=(type& a, const type& b)\
{\
using T = std::underlying_type_t<type>;\
a = type(static_cast<T>(a) | static_cast<T>(b));\
return a;\
}\
constexpr type& operator&=(type& a, const type& b)\
inline type& operator&=(type& a, const type& b)\
{\
using T = std::underlying_type_t<type>;\
a = type(static_cast<T>(a) & static_cast<T>(b));\
return a;\
}\
constexpr type operator~(const type& key)\
inline type operator~(const type& key)\
{\
using T = std::underlying_type_t<type>;\
return type(~static_cast<T>(key));\