Merge pull request #34 from lioncash/ltrt

LtRtProcessing: Make use of if constexpr in ClampFull()
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Phillip Stephens 2019-08-24 20:46:08 -07:00 committed by GitHub
commit efbb2f96ec
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1 changed files with 13 additions and 14 deletions

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@ -1,16 +1,17 @@
#include "LtRtProcessing.hpp"
#include <cmath>
#include "lib/audiodev/LtRtProcessing.hpp"
#include <algorithm>
#include <cmath>
#undef min
#undef max
namespace boo {
namespace {
template <typename T>
inline T ClampFull(float in) {
if (std::is_floating_point<T>()) {
return std::min<T>(std::max<T>(in, -1.f), 1.f);
constexpr T ClampFull(float in) {
if constexpr (std::is_floating_point_v<T>) {
return std::clamp(in, -1.f, 1.f);
} else {
constexpr T MAX = std::numeric_limits<T>::max();
constexpr T MIN = std::numeric_limits<T>::min();
@ -23,6 +24,7 @@ inline T ClampFull(float in) {
return in;
}
}
} // Anonymous namespace
#if INTEL_IPP
@ -237,19 +239,16 @@ LtRtProcessing::LtRtProcessing(int _5msFrames, const AudioVoiceEngineMixInfo& mi
m_inMixInfo.m_channelMap.m_channels[3] = AudioChannel::RearLeft;
m_inMixInfo.m_channelMap.m_channels[4] = AudioChannel::RearRight;
int samples = m_windowFrames * (5 * 2 + 2 * 2);
const int samples = m_windowFrames * (5 * 2 + 2 * 2);
switch (mixInfo.m_sampleFormat) {
case SOXR_INT16_I:
m_16Buffer.reset(new int16_t[samples]);
memset(m_16Buffer.get(), 0, sizeof(int16_t) * samples);
m_16Buffer = std::make_unique<int16_t[]>(samples);
break;
case SOXR_INT32_I:
m_32Buffer.reset(new int32_t[samples]);
memset(m_32Buffer.get(), 0, sizeof(int32_t) * samples);
m_32Buffer = std::make_unique<int32_t[]>(samples);
break;
case SOXR_FLOAT32_I:
m_fltBuffer.reset(new float[samples]);
memset(m_fltBuffer.get(), 0, sizeof(float) * samples);
m_fltBuffer = std::make_unique<float[]>(samples);
break;
default:
break;
@ -259,7 +258,7 @@ LtRtProcessing::LtRtProcessing(int _5msFrames, const AudioVoiceEngineMixInfo& mi
template <typename T>
void LtRtProcessing::Process(const T* input, T* output, int frameCount) {
#if 0
for (int i=0 ; i<frameCount ; ++i)
for (int i = 0; i < frameCount; ++i)
{
output[i * 2] = input[i * 5 + 3];
output[i * 2 + 1] = input[i * 5 + 4];